How do you solve this serial dilution problem? Please help!!?
I have looked up how to do serial dilution problems online and in my book...to no avail!
You are given a container of yeast cells at a concentration of 2.6x10^6 cells/mL. How would you prepare a suspension of yeast such that when you spread 1mL of that suspension onto appropriate media you would get about 100 cells? Can someone please explain how to work this problem?
Thank you so much M!!! I finally got it...like really got it!! I understood all the other problems. Thank you again. 
Think of it this way:
2.6x10^6 is the same as 260x10^4. To get it to 260 cells/mL requires performing tenfold serial dilutions four times. That means taking one mL of suspension and adding it to nine mL sterile dilution water, mixing it, and then diluting that again, until you've done it four times. Getting that 260 cells/mL to 100 cells per mL requires a 1 to 2.6 dilution, meaning that you add one mL to 1.6 mL sterile dilution water.
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